Question

If volume occupied by $CO_2$ molecules is negligible, then what will be the pressure $\left(\frac{p}{5.277}\right)$ exerted by one mole of $CO_{2}$ gas at $300\, K$? $\left(a = 3.592 atm L^{2} mol^{2}\right)$

• A. $7$
• B. $8$
• C. $9$
• D. $3$

Answer 1

Answer: (B)

$8$

Answer 2

$\left(p+\frac{an^{2}}{V^{2}}\right)$ $\left(V-nb\right)=nRT$ $\left(p+\frac{a}{V^{2}}\right)\left(V-b\right)=RT$ $\quad$ $\left(\because n=1\right)$ If b is negligible p $=\frac{RT}{V}-\frac{a}{V^{2}}$ The equation is quadratic in $V$ , thus $V=\frac{+RT\pm\sqrt{R^{2}T^{2}-4ap}}{2p}$ Since $V$ has one value at given $P$ and $T$, thus numericalvalue of discriminant = $0$ $R^{2}T^{2}=4ap$ $p=\frac{R^{2}T^{2}}{4a}$ $=\frac{\left(0.0821\right)^{2}\left(300\right)^{2}}{4\times3.592}$ $\quad$ $\therefore$ $\frac{p}{5.277}=8$