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Question

Physics Question on simple harmonic motion

If vibration of string is to be two times then tension in the string must be made :

A

eight times

B

four times

C

twice

D

half

Answer

four times

Explanation

Solution

Here: Initial vibration n1=nn_{1}=n, final vibration n2=2nn_{2}=2 n
Initial tension T1=TT_{1}=T
Vibration of frequency of string
n=12lTmn=\frac{1}{2 l} \sqrt{\frac{T}{m}}
nT\Rightarrow n \propto \sqrt{T}
Hence, n1n2=T1T2\frac{n_{1}}{n_{2}}=\sqrt{\frac{T_{1}}{T_{2}}}
or T1T2=(n1n2)2\frac{T_{1}}{T_{2}}=\left(\frac{n_{1}}{n_{2}}\right)^{2}
=(n2n)2=12=\left(\frac{n}{2 n}\right)^{2}=\frac{1}{2}
or T2=4T1T_{2}=4 T_{1}