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Question

Mathematics Question on Vector Algebra

If a.b=0\vec{a}.\vec{b}=0 and a+b\vec{a}+\vec{b} makes an angle 60° with a\vec{a} then

A

a=2b|\vec{a}|=2|\vec{b}|

B

2a=b2|\vec{a}|=|\vec{b}|

C

a=3b|\vec{a}|=\sqrt3|\vec{b}|

D

3a=b\sqrt3|\vec{a}|=|\vec{b}|

Answer

3a=b\sqrt3|\vec{a}|=|\vec{b}|

Explanation

Solution

The correct answer is (D) : 3a=b\sqrt3|\vec{a}|=|\vec{b}|.