Question

If $|\vec{a}\times\vec{b}|+|\vec{a}.\vec{b}|^2$=144 and $|\vec{a}|$ = 6, then $|\vec{b}|$ is equal to

• A. 6
• B. 3
• C. 2
• D. 4

Answer 1

Answer: (C)

2

Answer 2

The correct answer is (C) : 2.