Question

If $|\vec{a}\times\vec{b}|$ + $|\vec{a}.\vec{b}|^2=36$ and $|\vec{a}|=3$ then $|\vec{b}|$ is equal to

• A. 9
• B. 4
• C. 36
• D. 2

Answer 1

Answer: (A)

9

Answer 2

The correct answer is (A) : 9.