Question

If $\vec{a} = \hat{i} + \lambda \hat{j} + 2 \hat{k}$ and $\vec{b} = \mu \hat{i} + \lambda \hat{j} + 2 \hat{k}$ are orthogonal and if $|\vec{a} | = |\vec{b}|$, then $(\lambda, \mu)$ =

• A. $\left(\frac{1}{4} , - \frac{9}{4}\right)$
• B. $\left( - \frac{1}{4} , \frac{9}{4}\right)$
• C. $\left(\frac{7}{4} ,\frac{1}{4}\right)$
• D. $\left(\frac{1}{4} , \frac{7}{4}\right)$

Answer 1

Answer: (D)

$\left(\frac{1}{4} , \frac{7}{4}\right)$

Answer 2

The vectors $\vec{a} = \hat{i} + \lambda \hat{j} + 2 \hat{k}$ and $\vec{b} = \mu \hat{i} + \lambda \hat{j} + 2 \hat{k}$ are orthogonal .
$\therefore \:\:\: \vec{a} . \vec{b} = 0$
$\Rightarrow \:\:\: \mu +\lambda - 2 = 0 \:\: \Rightarrow \: \mu + \lambda = 2$ ....(i)
Since , $|\vec{a} | = | \vec{b}|$
$\therefore\:\:\: \sqrt{1+\lambda^{2}+4} = \sqrt{\mu^{2} +1+1} \Rightarrow \lambda^{2} + 5 = \mu^{2} + 2$
$\Rightarrow \lambda ^{2} + 5 =\left(2 -\lambda\right)^{2} + 2$ [using (i)]
$\Rightarrow \lambda ^{2} + 5 =4 +\lambda ^{2} - 4\lambda + 2$
$\Rightarrow \lambda = \frac{1}{4}$
$\therefore\:\:\: \mu = 2- \frac{1}{4} = \frac{7}{4}$ Hence $\left(\lambda,\mu\right) = \left(\frac{1}{4} , \frac{7}{4}\right)$