Question
Mathematics Question on Vectors
If ∣a∣=3,∣b∣=2,∣c∣=1 then the value of ∣a.b+b.c+c.a∣ is (given that a+b+c=0)
A
-7
B
7
C
14
D
-14
Answer
7
Explanation
Solution
a+b+c=0 ⇒(a+b+c)2=0 ⇒∣a∣2+b2+∣c∣2+2(a.b+b.c+c.a)=0 ⇒9+4+1+2(a.b+b.c+c.a)=0 ⇒a.b+b.c+c.a=7