Question
Question: If \({\vec a_1}\) and \({\vec a_2}\) are two non collinear unit vector and if \(\left| {{{\vec a}_1}...
If a1 and a2 are two non collinear unit vector and if ∣a1+a2∣=3 then find the value of (a1−a2)(2a1+a2)
(A) 2
(B) 23
(C) 21
(D) 1
Solution
The relation between the two unit vectors is given by ∣a1+a2∣=3. Squaring on both sides and simplifying the dot product find the value of θ. Now, expand (a1−a2)(2a1+a2) and after simplifying the dot product again substitute the values of both vectors and θ. On evaluating further, we get the required value.
Complete step-by-step solution:
a1 and a2 are two non-collinear unit vectors so their magnitude is equal one.
It is given that, ∣a1+a2∣=3
Squaring on both sides.
∣a1+a2∣2=(3)2
∣a1∣2+∣a2∣2+2a1.a2=3
1+1+2∣a1∣∣a2∣cosθ=3
2×1×1×cosθ=3−2
cosθ=21
We need to find the value of (a1−a2)(2a1+a2)
Multiply both to get four individual terms.
=2∣a1∣2−2a1.a2+a1.a2−∣a2∣2
=2−a1.a2−1
=1−∣a1∣∣a2∣cosθ
Substitute the value of θ .
=1−1×1×21
=21
Hence, the value of (a1−a2)(2a1+a2) is 21 and the correct option is C.
Note: Collinear vectors are those vectors which act along the same line. So, the angle between them can be zero or 1800. Coplanar vectors are where three vectors lie in the same plane. Equal, parallel, anti-parallel, collinear, zero, unit, orthogonal, polar, axial, coplanar and negative are the types of vectors.