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Question: If \(Var(x) = \frac{21}{4}\) and \(Var(y) = 21\)and\(r = 1\), then standard error of \(y\) is...

If Var(x)=214Var(x) = \frac{21}{4} and Var(y)=21Var(y) = 21andr=1r = 1, then standard error of

yy is

A

0

B

12\frac{1}{2}

C

14\frac{1}{4}

D

1

Answer

0

Explanation

Solution

Sy=σy1−r2=σy1−1=0S_{y} = \sigma_{y}\sqrt{1 - r^{2}} = \sigma_{y}\sqrt{1 - 1} = 0.