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Question

Physics Question on Electromagnetic waves

If ε0{\varepsilon}_0 and μ0{\mu}_0 are the electric permittivity and magnetic permeability in a free space, ε\varepsilon and μ\mu are the corresponding quantities in medium, the index and refraction of the medium is

A

ε0μ0εμ\sqrt{ \frac{ {\varepsilon}_0 {\mu}_0}{\varepsilon \mu }}

B

εμε0μ0\sqrt{ \frac{\varepsilon \mu}{{\varepsilon}_0 {\mu}_0}}

C

ε0μεμ0\sqrt{ \frac{{\varepsilon}_0 \mu }{\varepsilon {\mu}_0}}

D

εε0\sqrt{ \frac{\varepsilon}{{\varepsilon}_0}}

Answer

εμε0μ0\sqrt{ \frac{\varepsilon \mu}{{\varepsilon}_0 {\mu}_0}}

Explanation

Solution

c=1μ0ε0c= \frac{ 1}{ \sqrt{{\mu}_0 { \varepsilon}_0 }}(free space)
v=1μεv= \frac{1}{ \sqrt{\mu \varepsilon}} (medium)
μ=cv=μεμ0ε0\therefore \, \, \, \, \, \mu = \frac{c}{v} = \sqrt{ \frac{ \mu \varepsilon }{ { \mu}_0 {\varepsilon}_0 }}