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Question

Physics Question on Gravitation

If vev_e is escape velocity and vov _o is orbital velocity of a satellite for orbit close to the earth's suface, then these are related by

A

vo=2vev_o = \sqrt 2v_e

B

vo=vev_o = v_e

C

ve=2vov_e = \sqrt 2v_o

D

ve=2v_e = \sqrt 2

Answer

ve=2vov_e = \sqrt 2v_o

Explanation

Solution

Escape velocity, ve=2GMR...(i)v_e = \sqrt \frac {2GM}{R} \, \, \, \, \, \, ...(i)
where M and R be the mass and radius of the earth respectively.
The orbital velocity of a satellite close to the earth's surface is
vo=GMR...(ii)v_o = \sqrt \frac {GM}{R} \, \, \, \, \, \, \, \, \, \, ...(ii)
From (i) and (ii), we get
ve=2vov_e = \sqrt {2v_o}