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Question

Physics Question on Waves

If υs\upsilon_{s} is the velocity of sound in air and υ\upsilon is the rmsrms value, then

A

υs>υ\upsilon_{s} >\,\upsilon

B

υs=υ\upsilon_{s} =\upsilon

C

υs=υ[γ3]1/2\upsilon_{s} =\upsilon \left[\frac{\gamma}{3}\right]^{1 /2}

D

υs=υ[3γ]1/2\upsilon_{s} =\upsilon \left[\frac{3}{\gamma}\right]^{1 /2}

Answer

υs=υ[γ3]1/2\upsilon_{s} =\upsilon \left[\frac{\gamma}{3}\right]^{1 /2}

Explanation

Solution

Velocity of sound in air is vs=γPρ(i)v_{s}=\sqrt{\frac{\gamma P}{\rho}}\quad\ldots\left(i\right) Its rmsrms velocity is v=3Pρ(ii)v=\sqrt{\frac{3P}{\rho}}\quad\ldots\left(ii\right) Divide (i)\left(i\right) by (ii)\left(ii\right), we get vsv=γ3\frac{v_{s}}{v}=\sqrt{\frac{\gamma}{3}} vs=γ3vv_{s}=\sqrt{\frac{\gamma}{3}}v or vs<vv_{s} < v