Question
Question: If uncertainty in position and momentum are equal then uncertainty in velocity is: A. \(\sqrt {\df...
If uncertainty in position and momentum are equal then uncertainty in velocity is:
A. πh
B. 2πh
C. 2m1πh
D. m1πh
Solution
Heisenberg’s uncertainty principle states that the position and momentum of a particle cannot be determined simultaneously with precision. Mathematically, it is expressed as Δx⋅Δpx⩾4πh. Here, Δx is the uncertainty in position and Δpx is the uncertainty in momentum.
Complete step by step solution:
We know that the Heisenberg’s uncertainty principle is mathematically expressed as,
Δx⋅Δpx⩾4πh or Δx⋅Δp=4πh
where Δx is the uncertainty in position,
Δpx is the uncertainty in momentum,
h is the Planck’s constant.
We are given that the uncertainty in position and momentum are equal. Thus,
Δx=Δpx
We know that the momentum of a particle is the product of the mass of the particle and the velocity with which the particle is moving. Thus,
Δp=mΔv
where Δpx is the uncertainty in momentum,
m is the mass of the particle,
Δv is the velocity of the particle.
Thus, the mathematical expression for Heisenberg’s uncertainty principle is,
Δx⋅mΔv=4πh
We are given that the uncertainty in position and momentum are equal. Thus,
Δx=mΔv
Thus, the mathematical expression for Heisenberg’s uncertainty principle is,
mΔv⋅mΔv=4πh
Δv2=m24πh
Take the square root on both sides of the equation. Thus,
Δv2=2m1πh
Thus, the uncertainty in velocity is 2m1πh.
Thus, if uncertainty in position and momentum are equal then uncertainty in velocity is 2m1πh.
**Thus, the correct option is (C) 2m1πh.
Note: **
Heisenberg’s uncertainty principle is not applicable to the macroscopic particles but it is applicable only to the microscopic particles i.e. the uncertainty in position and the uncertainty in momentum must be along the same axis. We can say that if the momentum is parallel to an axis is precisely known then the position along the same axis is uncertain or vice versa.