Solveeit Logo

Question

Question: If uncertainty in position and momentum are equal then uncertainty in velocity is: A. \(\sqrt {\df...

If uncertainty in position and momentum are equal then uncertainty in velocity is:
A. hπ\sqrt {\dfrac{h}{\pi }}
B. h2π\sqrt {\dfrac{h}{{2\pi }}}
C. 12mhπ\dfrac{1}{{2m}}\sqrt {\dfrac{h}{\pi }}
D. 1mhπ\dfrac{1}{m}\sqrt {\dfrac{h}{\pi }}

Explanation

Solution

Heisenberg’s uncertainty principle states that the position and momentum of a particle cannot be determined simultaneously with precision. Mathematically, it is expressed as ΔxΔpxh4π\Delta x \cdot \Delta {p_x} \geqslant \dfrac{h}{{4\pi }}. Here, Δx\Delta x is the uncertainty in position and Δpx\Delta {p_x} is the uncertainty in momentum.

Complete step by step solution:
We know that the Heisenberg’s uncertainty principle is mathematically expressed as,
ΔxΔpxh4π\Delta x \cdot \Delta {p_x} \geqslant \dfrac{h}{{4\pi }} or ΔxΔp=h4π\Delta x \cdot \Delta p = \dfrac{h}{{4\pi }}
where Δx\Delta x is the uncertainty in position,
Δpx\Delta {p_x} is the uncertainty in momentum,
hh is the Planck’s constant.
We are given that the uncertainty in position and momentum are equal. Thus,
Δx=Δpx\Delta x = \Delta {p_x}
We know that the momentum of a particle is the product of the mass of the particle and the velocity with which the particle is moving. Thus,
Δp=mΔv\Delta p = m\Delta v
where Δpx\Delta {p_x} is the uncertainty in momentum,
mm is the mass of the particle,
Δv\Delta v is the velocity of the particle.
Thus, the mathematical expression for Heisenberg’s uncertainty principle is,
ΔxmΔv=h4π\Delta x \cdot m\Delta v = \dfrac{h}{{4\pi }}
We are given that the uncertainty in position and momentum are equal. Thus,
Δx=mΔv\Delta x = m\Delta v
Thus, the mathematical expression for Heisenberg’s uncertainty principle is,
mΔvmΔv=h4πm\Delta v \cdot m\Delta v = \dfrac{h}{{4\pi }}
Δv2=hm24π\Delta {v^2} = \dfrac{h}{{{m^2}4\pi }}
Take the square root on both sides of the equation. Thus,
Δv2=12mhπ\Delta {v^2} = \dfrac{1}{{2m}}\sqrt {\dfrac{h}{\pi }}
Thus, the uncertainty in velocity is 12mhπ\dfrac{1}{{2m}}\sqrt {\dfrac{h}{\pi }} .
Thus, if uncertainty in position and momentum are equal then uncertainty in velocity is 12mhπ\dfrac{1}{{2m}}\sqrt {\dfrac{h}{\pi }} .

**Thus, the correct option is (C) 12mhπ\dfrac{1}{{2m}}\sqrt {\dfrac{h}{\pi }} .

Note: **
Heisenberg’s uncertainty principle is not applicable to the macroscopic particles but it is applicable only to the microscopic particles i.e. the uncertainty in position and the uncertainty in momentum must be along the same axis. We can say that if the momentum is parallel to an axis is precisely known then the position along the same axis is uncertain or vice versa.