Question

If two waves represented by $y_{1}=4\sin \,\omega t$ and $y_{2}=3\sin \left( \omega t+\frac{\pi }{3} \right)$ interfere at a point. The amplitude of the resulting wave will be about

• A. 7
• B. 6
• C. 5
• D. 3.5

Answer 1

Answer: (B)

6

Answer 2

Resulting amplitude of two interfering waves $A=\sqrt{a_{1}^{2}+a_{2}^{2}+2 a_{1} a_{2} \cos \phi}$ Here, $\phi=\pi / 3, a_{1}=4, a_{2}=3$ $\Rightarrow A \simeq 6$