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Question: If two vectors \(2\widehat{i} + 3\widehat{j} - \widehat{k}\) and \(- 4\widehat{i} - 6\widehat{j} - \...

If two vectors 2i^+3j^k^2\widehat{i} + 3\widehat{j} - \widehat{k} and 4i^6j^λk^- 4\widehat{i} - 6\widehat{j} - \lambda\widehat{k} are parallel to each other then value of λ be.

A

0

B

2

C

3

D

4

Answer

2

Explanation

Solution

Let A=2i^+3j^k^\overset{\rightarrow}{A} = 2\widehat{i} + 3\widehat{j} - \widehat{k} and B=4i^6j^+λk^\overset{\rightarrow}{B} = - 4\widehat{i} - 6\widehat{j} + \lambda\widehat{k}

A\overset{\rightarrow}{A} and B\overset{\rightarrow}{B} are parallel to each other

a1b1=a2b2=a3b3\frac{a_{1}}{b_{1}} = \frac{a_{2}}{b_{2}} = \frac{a_{3}}{b_{3}} i.e. 24=36=1λλ=2\frac{2}{- 4} = \frac{3}{- 6} = \frac{- 1}{\lambda} \Rightarrow \lambda = 2.