Question

If two temperatures differ by $25$ degrees on Celsius scale, the difference of temperature on Fahrenheit scale is
A) ${65^ \circ }$
B) ${45^ \circ }$
C) ${38^ \circ }$
D) ${25^ \circ }$

Answer 1

We have mainly three scales to measure temperatures. Each scale has a different relation with other scales. In this question, we can calculate the temperature on Fahrenheit scale by using the relation between Celsius scale and Fahrenheit scale.

Complete step by step solution: - In the question, there are two temperature scales mentioned. One is Celsius scale and the other is Fahrenheit scale.
We know that for a temperature difference, Celsius scale is always equal to five-ninths of a Fahrenheit degree.
Or $C = \dfrac{5}{9}F$
In other words, we can say that for a temperature difference, Fahrenheit degree is always equal to nine-fifths of a Celsius degree.
Or $F = \dfrac{9}{5}C$
According to the question, the difference between two temperatures on a Celsius scale is $25$degrees.
So,
Difference on the Fahrenheit scale $= 25 \times \dfrac{9}{5}$
$\Rightarrow$ Difference on the Fahrenheit scale $= 45$ degree
Hence, the difference on Fahrenheit scale is $45$degree.

Therefore, option B is correct.

Additional Information:- There are three scales which can measure the temperature of a body namely Celsius, Fahrenheit and Kelvin. The Celsius scale is a $100$ degree scale. The minimum temperature on a Celsius scale is ${0^ \circ }C$ and the highest temperature is${100^ \circ }C$ . The Fahrenheit scale is $180$ degree scale. The minimum temperature on a Fahrenheit scale is ${32^ \circ }F$ and the highest temperature is${212^ \circ }F$ . The Kelvin scale is a $100$degree scale. The minimum temperature on a Kelvin scale is ${272^ \circ }K$ and the highest temperature is${372^ \circ }K$ .

Note:- In this question, we have to keep in mind that the relation between Celsius scale and Fahrenheit scale is not equal to the relation between Fahrenheit scale and Celsius scale. One relation is reciprocal to the other relation. In general, $32$ is added in five-ninths of the Celsius scale to convert it into Fahrenheit scale but here we have the difference 0in the two temperatures, so $32$ is neither added nor subtracted from any value.