Question
Question: If two tangents to an ellipse and one of its foci be given, prove that the locus of its centre is a ...
If two tangents to an ellipse and one of its foci be given, prove that the locus of its centre is a straight line.
Solution
Hint: Consider T as the tangent drawn to the ellipse. Use the equation to find the polar form of tangent. Take focus ‘S’ of the ellipse is (ae, 0) and for s′ (−ae,0). Find the polar form of Tangents to prove the locus of its centre is a straight line.
Complete step by step answer:
Let us consider T as the tangent that is drawn to the ellipse. TP and TQ are the two tangents from T, which has their focus at S. The focus S of the ellipse is (ae,0) and for S1 (−ae,0).
Hence we need to prove that ∠QTS1=∠PTS ( from figure).
The centre C of the ellipse is midway between S and S1 , which are the focus.
Let the coordinate of any point be (h,k) and equation to ellipse is
a2x2+b2y2=1............(1)
To find the polar form of tangent we have the equation a2xx1+b2yy1=1..............(2)
(h,k)=(x1,y1)
∴ Substituting values in (2)⇒a2xh+b2yk=1...........(3)
By hypothesis ⇒a2h2+b2k21=c is the length of perpendicular from centre (0,0) is given this
On squaring and cross multiplying we get
21=a4h2+b4k2
Now generalizing the locus of (h,k) , we get a4x2+b4y2=c21
We got the locus of its centre, so when S1 moves on TS1,C will move parallel to TS1 so that they will bisect the line SS1. Therefore we were able to prove that the locus of centre C is a straight line.
Note: Remember that two tangents drawn from any point to an ellipse subtend equal angle at the focus.