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Question: If two of the three feet of normals drawn from a point to the parabola \(y ^ { 2 } = 4 x\)be (1, 2) ...

If two of the three feet of normals drawn from a point to the parabola y2=4xy ^ { 2 } = 4 xbe (1, 2) and (1, – 2)then the third foot is

A

(2,22)( 2,2 \sqrt { 2 } )

B

(2,22)( 2 , - 2 \sqrt { 2 } )

C

(0,0)( 0,0 )

D

None of these

Answer

(0,0)( 0,0 )

Explanation

Solution

The sum of the ordinates of the foot =y1+y2+y3=0y _ { 1 } + y _ { 2 } + y _ { 3 } = 0

2+(2)+y3=0y3=0\therefore 2 + ( - 2 ) + y _ { 3 } = 0 \Rightarrow y _ { 3 } = 0