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Question

Mathematics Question on Probability

If two numbers pp and qq are chosen randomly from the set 1,2,3,4\\{1, 2, 3, 4\\} with replacement, then the probability that p24q p^2 \ge 4q is equal to

A

14\frac{1}{4}

B

316\frac{3}{16}

C

12\frac{1}{2}

D

716\frac{7}{16}

Answer

716\frac{7}{16}

Explanation

Solution

Total number of outcomes S = \\{(1, 1), (1, 2), (1, 3), (1, 4), (2, 1), (2, 2), (2, 3), (2,4), (3,1), (3,2), (3, 3), (3,4), (4,1), (4,2), (4, 3), (4,4)\\} n(S)=16 n(S) = 16 Number of favourable outcomes E=(2,1),(3,1),(3,2),(4,1),(4,2),(4,3),(4,4) E = \\{(2,1), (3,1), (3,2), (4,1), (4,2), (4,3), (4,4)\\} n(E)=7 n(E) = 7 \therefore Required probability =n(E)n(S)= \frac{n\left(E\right)}{n\left(S\right) } =716 = \frac{7}{16}