Solveeit Logo

Question

Question: If two like charges of magnitude 1 × 10<sup>–9</sup> coulomb and 9 ×10<sup>–9</sup> coulomb are sepa...

If two like charges of magnitude 1 × 10–9 coulomb and 9 ×10–9 coulomb are separated by a distance of 1 meter, then the point on the line joining the charges, where the force experienced by a charge placed at that point is zero, is-

A

0.25 m from the charge 1 × 10–9coul

B

0.75 m from the charge 9 × 10–9coul

C

Both A and B

D

At all points on the line joining the charges

Answer

Both A and B

Explanation

Solution

Q Force on charge q is zero

\thereforeF21 = F23

or kqq1x2\frac { \mathrm { kqq } _ { 1 } } { \mathrm { x } ^ { 2 } } = kqq2(1x)2\frac { \mathrm { kqq } _ { 2 } } { ( 1 - \mathrm { x } ) ^ { 2 } }

or 1×109x2\frac { 1 \times 10 ^ { - 9 } } { \mathrm { x } ^ { 2 } } =

or 1x\frac { 1 } { x } = 31x\frac { 3 } { 1 - x }

or 1 – x = 3x

or x = 0.25 m from 1 × 10–9C

\ From 9 × 10–9C, distance

= 1 – x

= 1 – 0.25

= 0.75