Question

If two dice are thrown together, then the probability of throwing a sum of atleast 9 is

• A. 1/18
• B. 7/18
• C. 13/18
• D. 5/18

Answer 1

Answer: (D)

5/18

Answer 2

N(S) = 6² = 36

Let E be the event of throwing atleast 9.

E = {(3, 6), (4, 5), (5, 4), (6, 3), (4, 6), (5, 5), (6, 4), (5, 6), (6, 5), (6, 6)}

N(5) = 10; P(5) = $\frac { 10 } { 36 } = \frac { 5 } { 18 }$.