Question

If time of flight of a projectile is 10 seconds. Range is 500 m. The maximum height attained by it will be

• A. 125 m
• B. 50 m
• C. 100 m
• D. 150 m

Answer 1

Answer: (A)

125 m

Answer 2

$T = \frac{2u\sin\theta}{g} = 10\sec$ ⇒ $u\sin\theta = 50$ so $a$

$= \frac{(50)^{2}}{2 \times 10} = 125m$.