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Question

Physics Question on Cells, Emf, Internal Resistance

If three cells are connected in parallel as shown in figure, then equivalent emf would be:
3 cells

A

Eeq=i=03Ei/ri/i=03riE_{eq}=\displaystyle\sum_{i=0}^{3}E_i/r_i/\displaystyle\sum_{i=0}^{3}r_i

B

Eeq=i=03ri/Ei/i=031/EiE_{eq}=\displaystyle\sum_{i=0}^{3}r_i/E_i/\displaystyle\sum_{i=0}^{3}1/E_i

C

Eeq=i=13Ei/ri/i=131/riE_{eq}=\displaystyle\sum_{i=1}^{3}E_i/r_i/\displaystyle\sum_{i=1}^{3}1/r_i

D

Eeq=i=13ri/Ei/i=13riE_{eq}=\displaystyle\sum_{i=1}^{3}r_i/E_i/\displaystyle\sum_{i=1}^{3}r_i

Answer

Eeq=i=13Ei/ri/i=131/riE_{eq}=\displaystyle\sum_{i=1}^{3}E_i/r_i/\displaystyle\sum_{i=1}^{3}1/r_i

Explanation

Solution

The correct option is(C):Eeq=i=13Ei/ri/i=131/riE_{eq}=\displaystyle\sum_{i=1}^{3}E_i/r_i/\displaystyle\sum_{i=1}^{3}1/r_i