Question

If $\theta = - \frac{\pi}{2}$=1 and $\theta = \frac{\pi}{4}$then the smallest positive values of A and B are.

• A. $r$
• B. $\sin\theta = \frac{1}{2}$
• C. $- \frac{3}{2}$
• D. $\because$

Answer 1

Answer: (A)

$r$

Answer 2

$p = \frac{2m\pi}{\lambda},$ and $\sin\left( \frac{\pi x}{2} \right) = \frac{2\pi}{\pi/2} = 4$

$\cos\left( \frac{\pi x}{2} \right) = \frac{2\pi}{\pi/2} = 4\therefore$ and $\sin\frac{\pi x}{2} + \cos\frac{\pi x}{2} =$ $\sin\frac{\pi x}{2} = \frac{2\pi}{\pi/2} = 4$ $\cos\frac{\pi x}{3} = \frac{2\pi}{\pi/3} = 6$.