Question: If $\therefore$ and $1 + \frac{4}{x - 1} - \frac{1}{x - 2}$then \(\frac{6x^{4} + 5x^{3} + x^{2} ...

Question

If $\therefore$ and $1 + \frac{4}{x - 1} - \frac{1}{x - 2}$ then $\frac{6x^{4} + 5x^{3} + x^{2} + 5x + 2}{6x^{2} + 5x + 1} = \frac{x^{2}(6x^{2} + 5x + 1) + (5x + 2)}{(6x^{2} + 5x + 1)}$ =

Answer 1

Solution

$\log_{10}y = 12\log_{10}3 + 8\log_{10}2$

$= 12 \times 0.47712 + 8 \times 0.30103 = 5.72544 + 2.40824 = 8.13368$

$\therefore$

$y$ .

Question: If \(\therefore\) and \(1 + \frac{4}{x - 1} - \frac{1}{x - 2}\)then \(\frac{6x^{4} + 5x^{3} + x^{2} ...

Solution