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Question

Question: If there were only one type of charge in the universe, then...

If there were only one type of charge in the universe, then

A

sE.ds0\oint_{}^{}{s\overrightarrow{E}.d\overrightarrow{s} \neq 0} on any surface

B

if the charge is outside the surface

C

qε0\frac{q}{\varepsilon_{0}} if charges of magnitude q were inside the surface

D

Both (2) and (3) are correct

Answer

Both (2) and (3) are correct

Explanation

Solution

: According to Gauss’s theorem in electrostatics

E.ds=qε0\oint_{}^{}{\overrightarrow{E}.d\overrightarrow{s} = \frac{q}{\varepsilon_{0}}}

Here q is charge enclosed by the surface.

If the charge is outside the surface, therefore qinside=0q_{inside} = 0

Also , E.ds=0\oint_{}^{}{\overrightarrow{E}.d\overrightarrow{s} = 0}

So both (2) and (3) are correct.