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Chemistry Question on Quantum Mechanical Model of Atom

If the wavelength of photon is 2.2×10−112.2 \times 10^{-11} and h=6.6×10−34 Jsh = 6.6 \times 10^{-34} \, \text{Js}. Then momentum of photon

A

1.452 x 10-44 Kg ms-1

B

3 x 10-23 Kg ms-1

C

6.89 x 10-43 Kg ms-1

D

3.33 x 10-22 Kg ms-1

Answer

3 x 10-23 Kg ms-1

Explanation

Solution

The momentum of a photon can be calculated using the equation:
p=hλp = \frac{h}{\lambda}
Given:
λ=2.2×10−11 m\lambda = 2.2 \times 10^{-11} \, \text{m}
h=6.6×10−34 J sh = 6.6 \times 10^{-34} \, \text{J s}
Substituting the values into the equation, we have:
p=6.6×10−34 J s2.2×10−11 mp = \frac{6.6 \times 10^{-34} \, \text{J s}}{2.2 \times 10^{-11} \, \text{m}}

p=6.6×10−34 Js2.2×10−11 mp = \frac{6.6 \times 10^{-34} \, \text{Js}}{2.2 \times 10^{-11} \, \text{m}}
p ≈ 3 x 10^-23 Kg m/s
Therefore, the momentum of the photon is approximately (B) 3×10−23 kg m/s3 \times 10^{-23} \, \text{kg m/s}