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Question: If the velocity of sound in air is 320 m/s, the frequency of the fundamental node emitted by a tube ...

If the velocity of sound in air is 320 m/s, the frequency of the fundamental node emitted by a tube of length 1m closed at one end is –

A

80 Hz

B

240 Hz

C

320 Hz

D

400 Hz

Answer

80 Hz

Explanation

Solution

l = 1m

l = λ4\frac { \lambda } { 4 } ̃ l = 4m

v = 320 m/s

\ f = 3204\frac { 320 } { 4 } = 80 Hz