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Question

Question: If the vector \(\vec { a }\) = (c log<sub>2</sub> x) <img src="https://cdn.pureessence.tech/canvas...

If the vector a\vec { a } = (c log2 x) – 6 j^\hat { \mathrm { j } } + 3 k^\hat { \mathbf { k } } and

= (log2 x) + 2 j^\hat { \mathrm { j } } + (2c log2 x) make an obtuse angle for any x Ī (0, ) then the interval to which 'c' belongs is –

A

(0, )

B

(– , 0)

C

(– 4/3, 0)

D

(–1, 0) Č (0, 2/3)

Answer

(– 4/3, 0)

Explanation

Solution

For vectors and b\overrightarrow { \mathrm { b } } to be inclined at an obtuse angle

. b\overrightarrow { \mathrm { b } } < 0 , x Ī (0, )c(log2 x)2 – 12 + 6 c log2 x < 0 " x Ī

(0, )

cy2 + 6 < cy – 12 <0 y Ī R y

= log2 xc < 0 and 36 c2 + 48 c < 0

c < 0 c (3c + 4)

< 0c Ī (– 4/3, 0)