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Question: If the two lines of regression are \(4x + 3y + 7 = 0\) and \(3x + 4y + 8 = 0\), then the means of x ...

If the two lines of regression are 4x+3y+7=04x + 3y + 7 = 0 and 3x+4y+8=03x + 4y + 8 = 0, then the means of x and y are

A

47,117- \frac{4}{7}, - \frac{11}{7}

B

47,117- \frac{4}{7},\frac{11}{7}

C

47,117\frac{4}{7}, - \frac{11}{7}

D

4, 7

Answer

47,117- \frac{4}{7}, - \frac{11}{7}

Explanation

Solution

Since lines of regression pass through(xˉ,yˉ)(\bar{x},\bar{y}), hence the equation will be 4xˉ+3yˉ+7=04\bar{x} + 3\bar{y} + 7 = 0,3xˉ+4yˉ+8=03\bar{x} + 4\bar{y} + 8 = 0

On solving the above equations, we get the required answer xˉ=47\bar{x} = - \frac{4}{7} and yˉ=117\bar{y} = - \frac{11}{7}.