Question

If the trivial solution is the only solution of the system of equations $x - ky + z = 0$ $kx + 3y - kz = 0$ $3x +y - z = 0$ then the set of all values of k is :

• A. R -{2,-3}
• B. R -{2}
• C. R -{-3}
• D. {2,-3}

Answer 1

Answer: (A)

R -{2,-3}

Answer 2

$x - ky + z = 0$ $kx + 3y - kz = 0$ $3x +y - z = 0$ The given system of equations will have non trivial solution, if $\begin{vmatrix}1&-k&1\\\ k&3&-k\\\ 3&1&-1\end{vmatrix} = 0$ $\Rightarrow \ 1(-3 + k )+ k (-k + 3k )+1(k - 9) = 0$ $\Rightarrow \ k - 3+ 2k^2 + k - 9 = 0$ $\Rightarrow \ k^2 + k - 6 = 0$ $\Rightarrow \ k = -3, k = 2$ So the equation will have only trivial solution, when $k \in R - \\{2, - 3\\}$