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Physics Question on physical world

If the time period tt of the oscillation of a drop of liquid of density dd, radius rr, vibrating under surface tension ss is given by the formula t=r2bscda/2.t=\sqrt{r^{2b}s^{c}d^{a/2}}. It is observed that the time period is directly proportional to ds.\sqrt{\frac{d}{s}}. The value of bb should therefore be :

A

34\frac{3}{4}

B

3\sqrt{3}

C

32\frac{3}{2}

D

23\frac{2}{3}

Answer

32\frac{3}{2}

Explanation

Solution

Answer (c) 32\frac{3}{2}