Question
Physics Question on simple harmonic motion
If the time period of a pendulum at height R (Where R is radius of earth) from surface of earth is T1 and at height 2R it is T2, then
A
3T1=2T2
B
2T1=3T2
C
T1=3T2
D
3T1=4T2
Answer
3T1=2T2
Explanation
Solution
The Correct answer is option is (A) : 3T1=2T2