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Question

Physics Question on simple harmonic motion

If the time period of a pendulum at height R (Where R is radius of earth) from surface of earth is T1T_1 and at height 2R it is T2T_2, then

A

3T1=2T23T_1 = 2T_2

B

2T1=3T22T_1 = 3T_2

C

T1=3T2T_1 = 3T_2

D

3T1=4T23T_1 = 4T_2

Answer

3T1=2T23T_1 = 2T_2

Explanation

Solution

The Correct answer is option is (A) : 3T1=2T23T_1 = 2T_2