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Question

Physics Question on thermal properties of matter

If the temperature of hot black body is raised by 5%5\%, rate of heat energy radiated would be increased by how much percentage ?

A

12%12\%

B

22%22\%

C

32%32\%

D

42%42\%

Answer

22%22\%

Explanation

Solution

According to Stefan?? law, rate of energy radiated by a black body at absolute temperature TT is given by H=AσT4H=A\sigma T^{4} where AA is the area of the emitting surface. T=T+5100T=2120TT'=T+\frac{5}{100}T=\frac{21}{20}T HH=(TT)4\therefore \frac{H'}{H}=\left(\frac{T'}{T}\right)^{4} =(2120)4=(1.05)4=\left(\frac{21}{20}\right)^{4}=\left(1.05\right)^{4} %\% increase in rate of heat energy =HHH×100=\frac{H'-H}{H}\times 100 =[(1.05)41]×10022%=\left[\left(1.05\right)^{4}-1\right]\times 100\approx 22\%