Question
Physics Question on Laws of thermodynamics
If the temperature of a black body increased rom 27∘C to 327∘C , the radiation emitted increases by a fraction of:
A
16
B
8
C
4
D
2
Answer
16
Explanation
Solution
Radiation emitted T1=27+273=300 T2=327+273=600 E∝T4 E2E1=T24T14=(600300)4 E2E1=161 Hence, E2=16E1