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Question

Physics Question on Laws of thermodynamics

If the temperature of a black body increased rom 27C27{}^\circ C to 327C327{}^\circ C , the radiation emitted increases by a fraction of:

A

16

B

8

C

4

D

2

Answer

16

Explanation

Solution

Radiation emitted T1=27+273=300{{T}_{1}}=27+273=300 T2=327+273=600{{T}_{2}}=327+273=600 ET4E\propto {{T}^{4}} E1E2=T14T24=(300600)4\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{T_{1}^{4}}{T_{2}^{4}}={{\left( \frac{300}{600} \right)}^{4}} E1E2=116\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{1}{16} Hence, E2=16E1{{E}_{2}}=16{{E}_{1}}