Question

If the tangent at the point P on the circle x² + y² + 6x + 6y = 2 meets the straight line 5x – 2y + 6 = 0 at a point Q on the y-axis, then the length of PQ is -

• A. 4
• B. 2$\sqrt { 5 }$
• C. 5
• D. 3$\sqrt { 5 }$

Answer 1

Answer: (C)

5

Answer 2

Now Q (0, 3)

Ž \ PQ = $\sqrt { \mathrm { S } _ { 1 } }$ =$\sqrt { 0 + 9 + 0 + 18 - 2 }$ = 5