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Question: If the system of equations, a<sup>2</sup>x – by = a<sup>2</sup> – b & bx – b<sup>2</sup>y = 2 + 4 b...

If the system of equations, a2x – by = a2 – b & bx – b2y

= 2 + 4 b possess no solution, then –

A

a = 1, b = – 1

B

a = 1, b = – 2

C

a = – 1, b = – 1

D

a = – 1, b = 2

Answer

a = – 1, b = 2

Explanation

Solution

a2b\frac{a^{2}}{b}= bb2\frac{b}{b^{2}}¹ a2−b2+4b\frac{a^{2} - b}{2 + 4b} Ž a2b2 = b2 Ž b2(a2 – 1) Ž a = 1 or

– 1 & b = 0, If a = 1 then 2 + 4 b = b – b2 Ž b2 + 3 b + 2

= 0 Ž b = – 2 or – 1;

If a = – 1 then b = – 2 or – 1]