Question

If the surface tension of water is 0.06 N/m, then the capillary rise in a tube of diameter 1mm is $(\theta = 0^{o})$

• A. 1.22 cm
• B. 2.44 cm
• C. 3.12 cm
• D. 3.86 cm

Answer 1

Answer: (B)

2.44 cm

Answer 2

$h = \frac{2T\cos\theta}{rdg}$, [θ =0, $r = \frac{1}{2}mm = 0.5 \times 10^{- 3}m$,

$T = 0.06N/m$, d = $10^{3}kg/m^{3}$, g = 9.8 m/s² ]

$h = \frac{2 \times 0.06 \times \cos\theta}{0.5 \times 10^{- 3} \times 10^{3} \times 9.8} = 0.0244m = 2.44cm$