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Question

Physics Question on mechanical properties of fluid

If the surface tension of water is 0.06 N m−1{0.06\, N\, m^{-1}}, then the capillary rise in a tube of a diameter 1 mm is (Take θ\theta = 0?)

A

1.22 cm

B

2.44 cm

C

3.12 cm

D

3.86 cm

Answer

2.44 cm

Explanation

Solution

As h=2S cos⁡ θrρg h = \frac{ 2S \,\cos \, \theta}{r \rho g}
= 2×0.06×cos⁡ 0∘0.5×10−3×103×9.8\frac{ 2 \times 0.06 \times \cos \, 0^\circ}{0.5 \times 10^{-3} \times 10^3 \times 9.8}
= 2.44×10−2 m=2.44 cm{2.44 \times 10^{-2} \, m = 2.44 \, cm}