Question

If the supply of oxygen is limited, $H_{2}S$ reacts with $O_{2}$ to form

• A. $H_{2}O+SO_{3}$
• B. $H_{2}O+S$
• C. $H_{2}SO_{4}+S$
• D. $H_{2}O+SO_{2}$

Answer 1

Answer: (B)

$H_{2}O+S$

Answer 2

In limited supply of oxygen, $H _{2} S$ burns with blue flame and $S$ and $H _{2} O$ are the main products. $2 H _{2} S + O _{2} \longrightarrow 2 H _{2} O +2 S$ In excess of oxygen, $H _{2} S$ gives $SO _{2}$ and water as main product.