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Question: If the sum of the first \(14\) terms of \(AP\) is \(1050\) and its first term is \(10\), find the \(...

If the sum of the first 1414 terms of APAP is 10501050 and its first term is 1010, find the 20th20{\text{th}} term.

Explanation

Solution

Here we will simply apply the formula of the sum of the nn terms of APAP which is the Arithmetic progression and get the value of the common difference by this formula. Once we get the common difference dd then we can simply solve for 20th20{\text{th}} term by applying the formula of the nthn{\text{th}} term of APAP

Formula Used:
sum of n terms(Sn)=n2(2a+(n1)d){\text{sum of n terms}}({S_n}) = \dfrac{n}{2}(2a + (n - 1)d)
nth term=an=a+(n1)dn{\text{th term}} = {a_n} = a + (n - 1)d

Complete step-by-step answer:
AP or arithmetic progression is the sequence in which the different terms have the same common difference or we can say that the consecutive numbers differ by the same number. For example: in the sequence like 2,4,6,8,.......1002,4,6,8,.......100 we can see that the difference between each consecutive term is 22 as 42=64=86=24 - 2 = 6 - 4 = 8 - 6 = 2
Hence the given sequence is called the Arithmetic progression or AP
Here we are given that the sum of first 1414 terms ofAPAP is 10501050
So we can apply the formula of the sum of the nn terms which is
sum of n terms(Sn)=n2(2a+(n1)d){\text{sum of n terms}}({S_n}) = \dfrac{n}{2}(2a + (n - 1)d)
We know that
Sum=1050{\text{Sum}} = 1050
a=first term=10a = {\text{first term}} = 10
n=number of terms=14n = {\text{number of terms}} = 14
Here d=d = common difference
So substituting the values in the formula we get:
sum of n terms(Sn)=n2(2a+(n1)d){\text{sum of n terms}}({S_n}) = \dfrac{n}{2}(2a + (n - 1)d)
\Rightarrow 1050=142(2(10)+(141)d)1050 = \dfrac{{14}}{2}(2(10) + (14 - 1)d)
\Rightarrow 1050=7(20+13d)1050 = 7(20 + 13d)
\Rightarrow 10507=20+13d\dfrac{{1050}}{7} = 20 + 13d
\Rightarrow 150=20+13d150 = 20 + 13d
\Rightarrow 13d=13013d = 130
\Rightarrow d=10d = 10
Hence we get that the common difference of the given arithmetic progression is 1010 which means that each term of the given sequence is 1010 more than the previous one.
Now we have got the common difference and now we need to know the 20th20{\text{th}} term of the sequence.
So we apply the formula of the nthn{\text{th}} term of the AP we get
nth term=an=a+(n1)dn{\text{th term}} = {a_n} = a + (n - 1)d
Here we should know what the value of each variable in the question is:
an=nth term{a_n} = n{\text{th term}}
And a=a = first term=10 = 10
And n=20n = 20 as we need to find the 20th20{\text{th}} term
And d=10d = 10 as we had calculated earlier
an=10+(201)10{a_n} = 10 + (20 - 1)10
=10+(19)(10) =10+190 =200  = 10 + (19)(10) \\\ = 10 + 190 \\\ = 200 \\\
Hence we get that the 20th20{\text{th}} term of the sequence which is in AP is 200200.

Note: Here we need to understand the meaning of the Arithmetic progression and we should know what formula should be used in order to calculate the nthn{\text{th}} term and the sum of the n terms. We should not make calculation mistakes as these types of questions are simple but need just the formula and the values of the parameters used in the formula.