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Question: If the sum of first \[n\] terms of a series be \[5{n^2} + 2n\] , then its second term is: A) \[16...

If the sum of first nn terms of a series be 5n2+2n5{n^2} + 2n , then its second term is:
A) 1616
B) 1717
C) 2714\dfrac{{27}}{{14}}
D) 5615\dfrac{{56}}{{15}}

Explanation

Solution

To solve the problem, we have to find the first term and the sum of the first two numbers. For that, we have to substitute n by 1 and 2 we will get the first number of the series and adding the two numbers we will get the sum of the first two numbers of the series. Then by subtracting these two values we get the second term of the series.

Complete step-by-step answer:
It is given that; the sum of first nn terms of a series be 5n2+2n5{n^2} + 2n.
We have to find the second term.
To solve the sum, we have to find the first term and the sum of the first two numbers.
By substituting n by 1 and 2 we will get the first number of the series and the sum of the first two numbers of the series.
Now, substituting n=1n = 1 we get,
First term is,
\Rightarrow$$$5{(1)^2} + 2(1) = 7$$ Again, substituting $$n = 1$$ we get, Sum of first two terms is, \Rightarrow$$$5{(2)^2} + 2(2) = 24So,thesecondtermis So, the second term is24 - 7 = 17Hence,thesecondtermis Hence, the second term is17$$.

Hence, the correct option is B) 1717.

Note: An itemized collection of elements in which repetitions of any sort are allowed is known as a sequence, whereas series is the sum of all elements.
The sum of the terms of a sequence is called a series .
If a sequence is arithmetic or geometric there are formulas to find the sum of the first n terms, denoted Sn{S_n} , without actually adding all of the terms.
We can consider, Sn=5n2+2n{S_n} = 5{n^2} + 2n
n=1,S1=7n = 1,{S_1} = 7
n=2,S1=5.22+4=24n = 2,{S_1} = {5.2^2} + 4 = 24
So, the second term is S2S1=247=17{S_2} - {S_1} = 24 - 7 = 17
Hence, the second term is 1717.