Question

If the sum and the product of mean and variance of a binomial distribution are 24 and 128 respectively, then the probability of one or two successes is :

• A. $\frac{33}{2^{32}}$
• B. $\frac{33}{2^{29}}$
• C. $\frac{33}{2^{28}}$
• D. $\frac{33}{2^{27}}$

Answer 1

Answer: (C)

$\frac{33}{2^{28}}$

Answer 2

The correct option is:(C): $\frac{33}{2^{28}}$