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Question: If the straight lines \(x-4y+7=0\) and \(3x-12y+11=0\) are tangents to a circle. Then, the radius of...

If the straight lines x4y+7=0x-4y+7=0 and 3x12y+11=03x-12y+11=0 are tangents to a circle. Then, the radius of the circle is:
(A) 10317\dfrac{10}{3\sqrt{17}}
(B) 537\dfrac{5}{3\sqrt{7}}
(C) 1517\dfrac{15}{\sqrt{17}}
(D) 5317\dfrac{5}{3\sqrt{17}}
(E) 5313\dfrac{5}{3\sqrt{13}}

Explanation

Solution

For answering this question we will find the distance between the two given tangents as it is known as diameter for a circle and we know that the radius of a circle is half of the diameter of the circle. For finding the distance between any two parallel lines ax+by+c1=0ax+by+{{c}_{1}}=0 and ax+by+c2=0ax+by+{{c}_{2}}=0 we will use the formulae given as c1c2a2+b2\dfrac{\left| {{c}_{1}}-{{c}_{2}} \right|}{\sqrt{{{a}^{2}}+{{b}^{2}}}} .

Complete step by step answer:
Now considering from the question we have 2 straight lines which are the tangents of a circle. Then we can say that the distance between the 2 straight lines will be diameter because we know that the distance between 2 tangents is the diameter.
As we need the radius of the circle we will find the distance between the given 2 straight lines and divide it by 2 because the diameter is twice the radius.
The given straight lines are x4y+7=0x-4y+7=0 and 3x12y+11=03x-12y+11=0 .
The distance between any two parallel lines ax+by+c1=0ax+by+{{c}_{1}}=0 and ax+by+c2=0ax+by+{{c}_{2}}=0 is given as c1c2a2+b2\dfrac{\left| {{c}_{1}}-{{c}_{2}} \right|}{\sqrt{{{a}^{2}}+{{b}^{2}}}}.
Using the above formulae we can say that the distance between x4y+7=0x-4y+7=0 and x4y+113=0x-4y+\dfrac{11}{3}=0 which is similar to 3x12y+11=03x-12y+11=0 is given as 711312+42\dfrac{\left| 7-\dfrac{11}{3} \right|}{\sqrt{{{1}^{2}}+{{4}^{2}}}} .
Hence the diameter of the circle will be 10317\dfrac{10}{3\sqrt{17}} .
So the radius will be 5317\dfrac{5}{3\sqrt{17}} .
Hence we can conclude that for a circle having these 2 straight lines x4y+7=0x-4y+7=0 and 3x12y+11=03x-12y+11=0 as tangents the radius will be 5317\dfrac{5}{3\sqrt{17}} .

Hence, option D is correct.

Note: While answering questions of this type we should make a note that the diameter is twice the radius and not the radius itself. And we should divide the distance between the two parallel lines by 2 otherwise we will obtain a wrong option that is A in this case.