Question
Question: If the straight lines \(x-4y+7=0\) and \(3x-12y+11=0\) are tangents to a circle. Then, the radius of...
If the straight lines x−4y+7=0 and 3x−12y+11=0 are tangents to a circle. Then, the radius of the circle is:
(A) 31710
(B) 375
(C) 1715
(D) 3175
(E) 3135
Solution
For answering this question we will find the distance between the two given tangents as it is known as diameter for a circle and we know that the radius of a circle is half of the diameter of the circle. For finding the distance between any two parallel lines ax+by+c1=0 and ax+by+c2=0 we will use the formulae given as a2+b2∣c1−c2∣ .
Complete step by step answer:
Now considering from the question we have 2 straight lines which are the tangents of a circle. Then we can say that the distance between the 2 straight lines will be diameter because we know that the distance between 2 tangents is the diameter.
As we need the radius of the circle we will find the distance between the given 2 straight lines and divide it by 2 because the diameter is twice the radius.
The given straight lines are x−4y+7=0 and 3x−12y+11=0 .
The distance between any two parallel lines ax+by+c1=0 and ax+by+c2=0 is given as a2+b2∣c1−c2∣.
Using the above formulae we can say that the distance between x−4y+7=0 and x−4y+311=0 which is similar to 3x−12y+11=0 is given as 12+427−311 .
Hence the diameter of the circle will be 31710 .
So the radius will be 3175 .
Hence we can conclude that for a circle having these 2 straight lines x−4y+7=0 and 3x−12y+11=0 as tangents the radius will be 3175 .
Hence, option D is correct.
Note: While answering questions of this type we should make a note that the diameter is twice the radius and not the radius itself. And we should divide the distance between the two parallel lines by 2 otherwise we will obtain a wrong option that is A in this case.