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Question

Question: If the straight line y = 2x + e is a tangent to the ellipse \(\frac{x^{2}}{8}\)+ \(\frac{y^{2}}{4}\...

If the straight line y = 2x + e is a tangent to the ellipse

x28\frac{x^{2}}{8}+ y24\frac{y^{2}}{4}= 1, then e will be equal to-

A

±4

B

±6

C

±1

D

± 8

Answer

±6

Explanation

Solution

y = 2x + e .. (1)

x28\frac{x^{2}}{8}+ y24\frac{y^{2}}{4}= 1 …(2)

Ž Q c2 = a2m2 + b2 Ž e2 = 8(2)2 + 4 Ž e = ?