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Question

Question: If the straight line \(y = m x\) is outside the circle \(x ^ { 2 } + y ^ { 2 } - 20 y + 90 = 0\) t...

If the straight line y=mxy = m x is outside the circle x2+y220y+90=0x ^ { 2 } + y ^ { 2 } - 20 y + 90 = 0 then

A

m> 3

B

m < 3

C

| m | > 3

D

| m | < 3

Answer

| m | < 3

Explanation

Solution

If the straight line y=mxy = m x is outside the given circle then perpendicular distance of line from centre of circle > radius of circle

101+m2>10\frac { 10 } { \sqrt { 1 + m ^ { 2 } } } > \sqrt { 10 }