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Question

Question: If the speed of revolution of a particle on the circumference of a circle and the speed gained in fa...

If the speed of revolution of a particle on the circumference of a circle and the speed gained in falling through a distance equal to half the radius are equal, then the centripetal acceleration will be

A

g2\frac{g}{2}

B

g4\frac{g}{4}

C

g3\frac{g}{3}

D

g

Answer

g

Explanation

Solution

Speed gain by body falling through a distance h is equal to v=2ghv = \sqrt{2gh} =2gr2= \sqrt{2g\frac{r}{2}} [As h=r2h = \frac{r}{2} given]

v=grv = \sqrt{gr}v2r=g\frac{v^{2}}{r} = g