Question
Chemistry Question on Atomic and Molecular Masses
If the speed of light is 3.0×108 ms–1, calculate the distance covered by light in 2.00 ns.
Answer
According to the question:
Time taken to cover the distance = 2.00 ns
= 2.00 x 10-9 s
Speed of light = 3.0 x 108 ms-1
Distance travelled by light in 2.00 ns
= Speed of light x Time taken
= (3.0 x 108 ms-1)(2.00 x 10-9 s)
= 6.00 x 10-1 m
= 0.600 m