Question

If the solution of $x\frac{dy}{dx}+y=x^3y^6$ is $\frac{1}{y^\alpha x^\beta}=\frac{\gamma}{2x^2}+C$, then value of $\alpha+\beta+\gamma$ is

• A. 5
• B. 10
• C. 15
• D. 20

Answer 1

Answer: (C)

15

Answer 2

The correct answer is(C): 15