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Question

Mathematics Question on Logarithmic Differentiation

If the solution of the equation logcosxcotx+4logsinxtanx=1,x(0,π2)\log _{\cos x} \cot x+4 \log _{\sin x} \tan x=1, x \in\left(0, \frac{\pi}{2}\right), is sin1(α+β2)\sin ^{-1}\left(\frac{\alpha+\sqrt{\beta}}{2}\right), where α\alpha, β\beta are integers, then α+β\alpha+\beta is equal to :

A

6

B

4

C

5

D

3

Answer

4

Explanation

Solution

The correct answer is (B) : 4
logcosx​cotx+4logsinx​tanx=1
⇒lncosxlncosx−lnsinx​+4lnsinxlnsinx−lncosx​=1
⇒(lnsinx)2−4(lnsinx)(lncosx)+4(lncosx)2=1
⇒lnsinx=2lncosx
⇒sin2x+sinx−1=0⇒sinx=2−1+5​​
∴α+β=4