Question
Mathematics Question on Logarithmic Differentiation
If the solution of the equation logcosxcotx+4logsinxtanx=1,x∈(0,2π), is sin−1(2α+β), where α, β are integers, then α+β is equal to :
A
6
B
4
C
5
D
3
Answer
4
Explanation
Solution
The correct answer is (B) : 4
logcosxcotx+4logsinxtanx=1
⇒lncosxlncosx−lnsinx+4lnsinxlnsinx−lncosx=1
⇒(lnsinx)2−4(lnsinx)(lncosx)+4(lncosx)2=1
⇒lnsinx=2lncosx
⇒sin2x+sinx−1=0⇒sinx=2−1+5
∴α+β=4